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For trees allowing multiple selection, force selection of a single row for now.

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I'm not immediately sure how to present multiple tree selections. I also don't know if I can control selection status from the input events. So, for the time being, we force a single row to be selected. This isn't the most ideal solution, but it makes debugging other issues easier, so I'll use it for now to unblock other work.
This commit is contained in:
Nolan Darilek 2019-09-20 10:28:17 -05:00
parent f11edefdb5
commit 77db176e20
1 changed files with 18 additions and 0 deletions
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18
accessible.gd
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@ -219,6 +219,20 @@ func tree_item_render():
tokens.append("selected") tokens.append("selected")
tts.speak(tokens.join(": "), true) tts.speak(tokens.join(": "), true)
func tree_item_deselect_all(item: TreeItem):
for i in range(node.columns):
item.deselect(i)
func tree_deselect_all_but(target: TreeItem, item: TreeItem):
if item != target:
tree_item_deselect_all(item)
if item.get_children():
tree_deselect_all_but(target, item.get_children())
var next = item.get_next()
while next:
tree_deselect_all_but(target, next)
next = next.get_next()
var prev_selected_cell var prev_selected_cell
var button_index var button_index
@ -226,6 +240,10 @@ var button_index
func tree_item_selected(): func tree_item_selected():
button_index = null button_index = null
var cell = node.get_selected() var cell = node.get_selected()
if cell:
cell.select(0)
if node.select_mode == Tree.SELECT_MULTI:
tree_deselect_all_but(cell, node.get_root())
if cell != prev_selected_cell: if cell != prev_selected_cell:
tree_item_render() tree_item_render()
prev_selected_cell = cell prev_selected_cell = cell